Posted by scooby9132002 on .
write an equation of the line containing the given point and parallel to the given line.
(5,8); 9x5y=2

math 
bobpursley,
put the equation in slope intercept form. A line parallel will have the same slope.

math 
Vipster,
9x5y = 2; y = 9/5x (2/5)
(using y=mx+c)
Slope of the given line = 9/5
hence the required line will have the same slope(9/5) since it is parallel.
Now putting the given point(5,8)in y=mx+c; since it passes through (5,8)
8 = m * 5 + c where m= slope = 9/5
or 8 = (9/5)*5 + c
or c = 89; c = 17
Equation of the required line is
y = 9/5 x + (17)
or 5y = 9x  85
or 9x  5y = 85 is the answer