Posted by **scooby9132002** on Sunday, October 18, 2009 at 4:10pm.

write an equation of the line containing the given point and parallel to the given line.

(5,-8); 9x-5y=2

- math -
**bobpursley**, Sunday, October 18, 2009 at 4:57pm
put the equation in slope intercept form. A line parallel will have the same slope.

- math -
**Vipster**, Sunday, October 18, 2009 at 5:05pm
9x-5y = 2; y = 9/5x -(2/5)

(using y=mx+c)

Slope of the given line = 9/5

hence the required line will have the same slope(9/5) since it is parallel.

Now putting the given point(5,-8)in y=mx+c; since it passes through (5,-8)

-8 = m * 5 + c where m= slope = 9/5

or -8 = (9/5)*5 + c

or c = -8-9; c = -17

Equation of the required line is

y = 9/5 x + (-17)

or 5y = 9x - 85

or 9x - 5y = 85 is the answer

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