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March 26, 2017

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write an equation of the line containing the given point and parallel to the given line.


(5,-8); 9x-5y=2

  • math - ,

    put the equation in slope intercept form. A line parallel will have the same slope.

  • math - ,

    9x-5y = 2; y = 9/5x -(2/5)
    (using y=mx+c)
    Slope of the given line = 9/5

    hence the required line will have the same slope(9/5) since it is parallel.
    Now putting the given point(5,-8)in y=mx+c; since it passes through (5,-8)

    -8 = m * 5 + c where m= slope = 9/5

    or -8 = (9/5)*5 + c
    or c = -8-9; c = -17

    Equation of the required line is

    y = 9/5 x + (-17)

    or 5y = 9x - 85

    or 9x - 5y = 85 is the answer

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