Posted by **eleanor** on Sunday, October 18, 2009 at 4:10pm.

how do i find the equaiton of the line tangent to the curve at the point defined by the given value of t.

1. x=t, y= the square root of t, t=1/4

2. x=sec^2t-1, y= tan t, t= -pi/4

## Answer This Question

## Related Questions

- Calculus Help Please!!! - Find an equation of the tangent line to the curve at ...
- calculus - Consider line segments which are tangent to a point on the right half...
- Calculus AB - Could someone please help me with these tangent line problems? 1) ...
- AP AB Calculus - Linear approximation: Consider the curve defined by -8x^2 + 5xy...
- Calculus AB - Sorry but I've got a lot of problems that I don't understand. 1) ...
- calculus - Consider the curve defined by 2y^3+6X^2(y)- 12x^2 +6y=1 . a. Show ...
- calculus - Find an equation of the tangent line to the curve at the given point...
- calculus - Find an equation of the tangent line to the curve at the given point...
- maths - given the equation of the curve as y=8-2x^2 (a) find equations of ...
- calculus - Given the curve defined by the equation y=cos^2(x) + sqrt(2)* sin(x) ...

More Related Questions