Friday

August 22, 2014

August 22, 2014

Posted by **eleanor** on Sunday, October 18, 2009 at 4:10pm.

1. x=t, y= the square root of t, t=1/4

2. x=sec^2t-1, y= tan t, t= -pi/4

- math -
**bobpursley**, Sunday, October 18, 2009 at 4:59pmI assume you are in calculus.

y= t^.5

y'=.5/t^.5

at t= .25 y'= .5/(.25)^5= .5/.5=1

y= mx + b

y= 1 x + b

put in x,y and solve for b.

**Related Questions**

calculus - Consider line segments which are tangent to a point on the right half...

calculus - Consider the curve defined by 2y^3+6X^2(y)- 12x^2 +6y=1 . a. Show ...

Calculus Help Please!!! - Find an equation of the tangent line to the curve at ...

maths - given the equation of the curve as y=8-2x^2 (a) find equations of ...

calculus - Given the curve defined by the equation y=cos^2(x) + sqrt(2)* sin(x) ...

Calculus - Damon - Find the line which passes through the point (0, 1/4) and is ...

Calculus - I have a two part question that pertains to a curve (r(x)) and its ...

math - With regards to question J: The variables x and y are connected by the ...

math - consider the curve defined by the equation y=a(x^2)+bx+c. Take a point(h,...

calc - for the parametric curve defined by x=3-2t^2 and y=5-2t ...sketch the ...