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December 18, 2014

December 18, 2014

Posted by **eleanor** on Sunday, October 18, 2009 at 4:10pm.

1. x=t, y= the square root of t, t=1/4

2. x=sec^2t-1, y= tan t, t= -pi/4

- math -
**bobpursley**, Sunday, October 18, 2009 at 4:59pmI assume you are in calculus.

y= t^.5

y'=.5/t^.5

at t= .25 y'= .5/(.25)^5= .5/.5=1

y= mx + b

y= 1 x + b

put in x,y and solve for b.

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