October 10, 2015

Homework Help: math

Posted by eleanor on Sunday, October 18, 2009 at 4:10pm.

how do i find the equaiton of the line tangent to the curve at the point defined by the given value of t.

1. x=t, y= the square root of t, t=1/4

2. x=sec^2t-1, y= tan t, t= -pi/4

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