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March 3, 2015

March 3, 2015

Posted by **Anonymous** on Sunday, October 18, 2009 at 4:09pm.

- physics -
**bobpursley**, Sunday, October 18, 2009 at 4:53pmThe original momentum is mv

the final momentum is m/2 * v1' + m/2*v2'

set the equal.

2v=v1' + v2'

a) v1'=2v-v2'

Now, energy.

1/2 m v^2+16.7=1/4 m v1'^2 + 1/4 m v2'^2

b) 2 v^2+ 16.7=v1'^2 + v2'^2

put the expression a) into b). multiply it out, gather terms, and solve the quadratic.

- physics -
**Anonymous II**, Tuesday, October 20, 2009 at 10:04pmbob- thanks, this helped alot. Just one thing though- when you're elminating the mass and the fractions in the Kinetic energy equation, you forgot about the normal number(energy added). It should be 4 * (16.7) / m after doing the elimination. The rest was perfect though, thanks!

- physics -
**tai**, Tuesday, October 20, 2009 at 11:45pmwow thanks

- physics -
**ghostanime2001**, Tuesday, December 11, 2012 at 2:51pmI don't understand why 16.7 J of kinetic energy has to be added to the initial kinetic energy of the mass instead of the final kinetic energy of the two split masses. Anyone have a good explanation ?

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