Posted by **Anonymous** on Sunday, October 18, 2009 at 4:09pm.

A block of mass 7.33 kg in outerspace is moving at 1.72 m/s with no external forces acting on it. After an explosion, the block is split into two parts both having mass equal to half the mass of the original block. The explosion supplies the two masses with an additional 16.7 J of kinetic energy. Neither mass leaves the line of original motion. Calculate the magnitude of the velocity of the mass that is moving at a greater velocity.

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**bobpursley**, Sunday, October 18, 2009 at 4:53pm
The original momentum is mv

the final momentum is m/2 * v1' + m/2*v2'

set the equal.

2v=v1' + v2'

a) v1'=2v-v2'

Now, energy.

1/2 m v^2+16.7=1/4 m v1'^2 + 1/4 m v2'^2

b) 2 v^2+ 16.7=v1'^2 + v2'^2

put the expression a) into b). multiply it out, gather terms, and solve the quadratic.

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**Anonymous II**, Tuesday, October 20, 2009 at 10:04pm
bob- thanks, this helped alot. Just one thing though- when you're elminating the mass and the fractions in the Kinetic energy equation, you forgot about the normal number(energy added). It should be 4 * (16.7) / m after doing the elimination. The rest was perfect though, thanks!

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**tai**, Tuesday, October 20, 2009 at 11:45pm
wow thanks

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**ghostanime2001**, Tuesday, December 11, 2012 at 2:51pm
I don't understand why 16.7 J of kinetic energy has to be added to the initial kinetic energy of the mass instead of the final kinetic energy of the two split masses. Anyone have a good explanation ?

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