Posted by Anonymous on Sunday, October 18, 2009 at 3:07pm.
Your answer is absolutely right, but just not yet simplified.
You should see that you can divide by 3 top and bottom. That reduces the constants to 121 and 33.
Now look at the x and q terms without the constants:
x^3q^6
------
xq^3
Can you divide top and bottom by x? By q? By q again?
so it is
121q^3x^2/33
Yes!
When you get confused because there are just too many letters and numbers, try to isolate them and look at one at a time. The secret of success is getting used to being confused. :-)
Thank you
You're welcome.
I was wondering is this right by factoring here is a example of what I am learning
x^2-5x-24/x^2-6x+9 * x-3/x-8
the answer that they got was
x+3/x-3
I am so confused because there are two examples and I am not sure what is right
x^2-5x-24 = (x-8)(x+3)
x^2-6x+9 = (x-3)(x-3)
Make sure you understand these two first!
Factoting x^2 + ax + b, you look for two numbers that ADD to a, but MULTIPLY to b. So in the first case, 6*4 = 24, but they don't add to 5, no matter where I put the minus. But -8 * 3 and -8 + 3 give me the answer I want.
I don't get the answer you give for the whole expression. Are the brackets in the right place?
Ah. I see. I was reading it differently.
(x^2-5x-24) (x-3)
--------- * ------
(x^2-6x+9) (x-8)
= ((x-8)(x+3)(x-3))/((x-3)(x-3)(x-8))
x-8 and x-3 cancel top and bottom, and leave you with:
(x+3)/(x-3)