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February 1, 2015

February 1, 2015

Posted by **Anonymous** on Sunday, October 18, 2009 at 3:07pm.

I get real confused with all this

Multiply, Simplify if possible

3x^3/11q^3 * 121q^6/9x

the answer I got was

363q^6x^3/99q^3x

can you please show me how if it is wrong

- Math -
**jim**, Sunday, October 18, 2009 at 3:12pmYour answer is absolutely right, but just not yet simplified.

You should see that you can divide by 3 top and bottom. That reduces the constants to 121 and 33.

Now look at the x and q terms without the constants:

x^3q^6

------

xq^3

Can you divide top and bottom by x? By q? By q again?

- Math -
**Anonymous**, Sunday, October 18, 2009 at 3:16pmso it is

121q^3x^2/33

- Math -
**jim**, Sunday, October 18, 2009 at 3:18pmYes!

When you get confused because there are just too many letters and numbers, try to isolate them and look at one at a time. The secret of success is getting used to being confused. :-)

- Math -
**Anonymous**, Sunday, October 18, 2009 at 3:18pmThank you

- Math -
**jim**, Sunday, October 18, 2009 at 3:20pmYou're welcome.

- Math -
**Anonymous**, Sunday, October 18, 2009 at 3:22pmI was wondering is this right by factoring here is a example of what I am learning

x^2-5x-24/x^2-6x+9 * x-3/x-8

the answer that they got was

x+3/x-3

I am so confused because there are two examples and I am not sure what is right

- Math -
**jim**, Sunday, October 18, 2009 at 3:31pmx^2-5x-24 = (x-8)(x+3)

x^2-6x+9 = (x-3)(x-3)

Make sure you understand these two first!

Factoting x^2 + ax + b, you look for two numbers that ADD to a, but MULTIPLY to b. So in the first case, 6*4 = 24, but they don't add to 5, no matter where I put the minus. But -8 * 3 and -8 + 3 give me the answer I want.

I don't get the answer you give for the whole expression. Are the brackets in the right place?

- Math -
**jim**, Sunday, October 18, 2009 at 4:00pmAh. I see. I was reading it differently.

(x^2-5x-24) (x-3)

--------- * ------

(x^2-6x+9) (x-8)

= ((x-8)(x+3)(x-3))/((x-3)(x-3)(x-8))

x-8 and x-3 cancel top and bottom, and leave you with:

(x+3)/(x-3)

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