I have 2 problems that I just need to know if they are right

1. Add, Simplify if possible
3/14w + 11/49w
Answer that I got was
21+22/98w
2. Add, simplify if possible
9b/3b-9 + 6b/9b-27
I am not sure about this one
I got two answers
81b+6b/34b-108 or
87b/34b-108
please help

1. is correct, but not completed:

(21+22)/98w (careful to use the brackets)
=43/98w

2. I went wrong on this one myself, by taking the question down wrong, but I have it straight now.

Divide 6b/(9b-27) top and bottom by 3. You can do that without changing its value. So

6b/(9b-27) = 2b/(3b-9)

Now you're left with 9b/(3b-9) + 2b(3b-9) and I'm sure you can see your way from there.

reduce all anwser to thir lowesr terms

reduce all anwser to thir lowesr terms 12/25 5/18?

To determine if the given expressions are simplified correctly, let's go through each problem step by step:

1. Add and simplify: 3/14w + 11/49w

To add these fractions, we need a common denominator. In this case, the least common multiple (LCM) of 14 and 49 is 98.

Next, we rewrite the fractions with the common denominator:

(3/14)w + (11/49)w = (3*7)/(14*7)w + (11*2)/(49*2)w = 21/98w + 22/98w

Now that the fractions have the same denominator, we can add them:

21/98w + 22/98w = (21+22)/98w = 43/98w

So, the simplified answer is 43/98w, which means your initial answer of 21+22/98w is incorrect.

2. Add and simplify: 9b/(3b-9) + 6b/(9b-27)

In this problem, we have two fractions with denominators that can be factored.

First, we factor the denominators:

3b-9 = 3(b-3)
9b-27 = 9(b-3)

Now, we can find the least common denominator, which is (b-3).

Next, we rewrite the fractions with the common denominator:

9b/(3b-9) + 6b/(9b-27) = 9b/(3(b-3)) + 6b/(9(b-3))

Now that the fractions have the same denominator, we can combine them:

9b/(3(b-3)) + 6b/(9(b-3)) = (9b + 6b)/(3(b-3)) = 15b/(3(b-3))

Simplifying further, we can cancel out the 3 in the numerator and denominator:

15b/(3(b-3)) = 5b/(b-3)

Therefore, the simplified answer is 5b/(b-3). Neither of your initial answers (81b+6b/34b-108 or 87b/34b-108) is correct.

Hope this clarifies the correct simplifications for both problems!