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December 18, 2014

December 18, 2014

Posted by **mia** on Sunday, October 18, 2009 at 10:35am.

hmm now.. how do i do this?

- maths -
**Reiny**, Sunday, October 18, 2009 at 10:51amyour equation will be

10x + 15y = 55 or

2x + 3y = 11 or 2x = 11 - 3y

now we want only positive integer values of x and y.

clearly x < 6 and y < 4

Furthermore, if y is even, 11 - 3y will be odd, therefore x cannot be an integer.

So y has to be odd, and less than 4

Mmmm now, what do you think?

- maths -
**mia**, Sunday, October 18, 2009 at 11:28amthank you very much!! xx (=

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