write a linear equation to model the situation. you have walked 4 miles on a trail. you continue to walk at a rate of 3 miles per hour for 5 hours.
please tell me how to do this!! thanks!
You have a start point 4 miles from the origin, when this story begins.
You then walk at a rate of speed for a specified time.
There really isn't much equationing (which isn't a word!) to be done here, since you know your speed and time:
Distance from start point =
4 miles
plus
3 miles per hour for 5 hours
s = 4 + 3 * 5
[<equationing (which isn't a word!)> hehe]
thanks for the help! :)
To model this situation with a linear equation, we need to understand the relationship between the distance you have walked and the time you have walked for. In this case, the relationship is that you initially walk 4 miles, and then continue walking at a rate of 3 miles per hour for 5 hours.
Let's break down the problem and write the equation step by step:
1. Firstly, we start with the initial distance you walked, which is 4 miles. We can represent this as a constant value. Let's call this distance "d1".
2. Next, you continue walking for 5 hours at a rate of 3 miles per hour. This means that for every hour you walk, you cover a distance of 3 miles. So, in 5 hours of walking, you would cover 5 multiplied by the rate of 3 miles per hour. We can represent this distance as another constant value. Let's call this distance "d2".
3. Finally, to represent the total distance you have walked, we need to sum up the initial distance (d1) and the additional distance covered during the 5-hour period (d2). Mathematically, we can write the total distance (d) as:
d = d1 + d2
Now let's substitute the values into the equation:
- The initial distance, d1, is 4 miles.
- The additional distance covered during the 5-hour period, d2, is calculated as the rate (3 miles per hour) multiplied by the time (5 hours), which gives us:
d2 = 3 miles/hour * 5 hours
Inserting these values into the equation, we get:
d = 4 miles + 3 miles/hour * 5 hours
Simplifying the equation:
d = 4 + 3 * 5
d = 4 + 15
d = 19
Therefore, the linear equation to model this situation is: d = 19.