Posted by **John** on Sunday, October 18, 2009 at 3:24am.

An object is moving along the parabola y = 3x^2. (a) When it passes through the point (2,12), its horizontal velocity is dx/dt = 3. What is its vertical velocity at that instant? (b) If it travels in such a way that dx/dt = 3 for all t, then what happens to dy/dt as t --> +infinity? (c) If, however, it travels in such a way that dy/dt remains constant, then what happens to dy/dt as t --> +infinity?

- Calculus -
**Reiny**, Sunday, October 18, 2009 at 8:24am
dy/dt = 6x(dx/dt)

so at (2,12) dx/dt = 3

then dy/dt = 6(2)(3) = 36

If dx/dt is always 3, then dy/dt = 18x

so as x --> + infinity , 18x ---> + inf.

and dy/dt --> + inf.

for c) I think you meant to say,

"then what happens to dx/dt as t --> +infinity?"

if dy/dt = c

then c = 18(dx/dt)

dx/dt = c/(18x), now as x becomes larger and larger, what happens to the c/(18x) , and as a result, what happens to dx/dt ?

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