the speed of train A is 16 mph slower than the speed of train B. Train A travels 210 miles in the same time it takes train B to travel 290 miles. Find the speed of each train.

Train A = 58 mph
Train B = 74 mph
Can you tell me if this is right

You could have tested your answers to realize you were wrong.

210/58 = 3.62
290/74 = 3.9

I got
Train A 42 mph
Train B 58 mph

test
210/42 = 5
290/58 = 5

Thank you I forgo about checking the answer

Yes, your answer is correct. Train A travels 210 miles in the same time it takes Train B to travel 290 miles. Let's solve this problem step by step to explain it in detail.

Let the speed of Train B be 'x' mph. According to the problem, Train A is 16 mph slower than Train B, so the speed of Train A is 'x - 16' mph.

To find the time taken by both trains, we can use the formula: time = distance / speed.

For Train A: time taken = 210 miles / (x - 16) mph

For Train B: time taken = 290 miles / x mph

As per the problem, both trains take the same time:

210 miles / (x - 16) mph = 290 miles / x mph

To solve this equation, we can cross multiply:

210x = 290(x - 16)

Solving this equation step by step:

210x = 290x - 4640

Combining like terms:

290x - 210x = 4640

80x = 4640

Dividing both sides by 80:

x = 58

So, the speed of Train B, denoted by 'x', is 58 mph.

The speed of Train A is 16 mph less than Train B, so the speed of Train A is (58 - 16) mph = 42 mph.

Therefore, Train A has a speed of 42 mph, and Train B has a speed of 58 mph. So your answer is correct.