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physics

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When a carpenter shuts off his circular saw, the 10.0-inch diameter blade slows from 4670 rpm to zero in 3.00 s.
1) What is the distance traveled by a point on the rim of the blade during the deceleration? (in ft}
2)What is the magnitude of the net displacement of a point on the rim of the blade during the deceleration? (in inch}

  • physics - ,

    The avg velocity is 4670rpm/2
    turns= avgwelocity*time
    distance=turns*PI*Diameter
    Net displacement?

    Even turn=0 displacement. Now, with the remainder, calculate the finalpoint, and the initial point. The difference is displacemetn

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