Posted by **HELP PLEASE** on Friday, October 16, 2009 at 11:58pm.

Suppose a basketball player is an excellent free throw shooter and makes 91% of his free throws (i.e., he has a 91% chance of making a single free throw). Assume that free throw shots are independent of one another. Suppose this player shoots five free throws. Find the probability that he makes all five throws.

- mAtH -
**Shelly**, Saturday, October 17, 2009 at 12:24am
hey im NOT sure, but i think it's 45.5% because 5 x 0.91 = 45.5

- mAtH -
**Reiny**, Saturday, October 17, 2009 at 7:59am
The probability that he makes five out of his five shots

= (.91)(.91)(.91)(.91)(.91)

= (.91)^5

= .624 or 62.4%

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