Posted by HELP PLEASE on Friday, October 16, 2009 at 11:58pm.
Suppose a basketball player is an excellent free throw shooter and makes 91% of his free throws (i.e., he has a 91% chance of making a single free throw). Assume that free throw shots are independent of one another. Suppose this player shoots five free throws. Find the probability that he makes all five throws.

mAtH  Shelly, Saturday, October 17, 2009 at 12:24am
hey im NOT sure, but i think it's 45.5% because 5 x 0.91 = 45.5

mAtH  Reiny, Saturday, October 17, 2009 at 7:59am
The probability that he makes five out of his five shots
= (.91)(.91)(.91)(.91)(.91)
= (.91)^5
= .624 or 62.4%
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