A pair of dice are rolled and the sum on their upturned faces is recorded. What is the probability that the sum showing is 7 given that one die is showing a 4?
well, then the other die must be a 3. and since there is 6 faces on a die and 3 is just one face, i guess it would be 1/6. I WOULD DOUBLE CHECK THOUGH, IM NOT SURE.
There are only 2 choices,\
3,4 or 4,3.
So the prob of getting those is 2/36
= 1/18
To find the probability that the sum showing is 7 given that one die is showing a 4, we can use conditional probability.
Let's first identify the sample space, which consists of all possible outcomes when rolling two dice. Each die has 6 sides, so the total number of outcomes is 6 x 6 = 36.
We need to find the favorable outcome, which is the pair of dice showing a sum of 7, given that one die is showing a 4.
When one die is showing a 4, there are 6 possibilities for the second die to get a sum of 7: (4, 3), (4, 3), (4, 3), (4, 3), (4, 3), and (4, 3).
So, the favorable outcome is 6.
Now, we can calculate the probability:
Probability = (Number of favorable outcomes) / (Total number of possible outcomes)
= 6 / 36
= 1 / 6
Therefore, the probability that the sum showing is 7 given that one die is showing a 4 is 1/6.