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April 18, 2014

April 18, 2014

Posted by **LIZ** on Friday, October 16, 2009 at 10:07pm.

(THE ANGLE OF V1 WITH RESPECT TO THE ORIGINAL V DIRECTION IS 30 DEGREES WHILE THE ANGLE OF V2 IS 60 DEGREES.)

- PHYSICS -
**lisa**, Thursday, October 22, 2009 at 2:59pmthe answer is v1 = 2*45*cos(30) = 77.9 m/s

- PHYSICS -
**...**, Thursday, October 22, 2009 at 9:58pmhow did u get tis answer lisa,,

- PHYSICS -
**natt**, Thursday, November 5, 2009 at 4:19amset x to initial rocket direction. so Vx=45m/s

1st conservation of linear momentum theorem in x direction:

m*45 = 1/2m*V1*cos30 + 1/2m*V2*cos60

cancel m and multiply by 2

90 = V1*cos30 + V2*cos 60

2nd conservation of linear momentum theorem in y direction. remember initial rocket Vy = 0

0 = 1/2*m*V1*sin30 - 1/2 *m*V2*sin60

put on opposite sides. 1/2 and m's cancel out.

therefore:

V1*sin30 = V2*sin60

Solve for V1 or V2 and plug in.

eventually if you solve for V1 and plug in:

90 = 1.5V2 + .5V2

2V2 = 90

V2 = 45m/s

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