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Post a New Question | Current Questions | Chat With Live Tutors
Posted by Rose on Friday, October 16, 2009 at 1:37pm.
When heated, calcium carbonate decomposes to yield calcium oxide and carbon dioxide gas via the reaction
CaCO3(s)---->CaO(s)+CO2(g)
How many grams of calcium carbonate are needed to produce 59.0L of carbon dioxide at STP?
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- Chemistry-Please help - DrBob222, Friday, October 16, 2009 at 3:14pm
1. Write the balanced equation.
2. Convert 59.0 L CO2 at STP to moles. moles = 59.0 L x (1 mole/22.4 L) = ??
3. Using the coefficients in the balanced equation, convert moles CO2 to moles CaCO3.
4. Convert moles CaCO3 to grams.
grams = moles x molar mass.
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