posted by Rose on .
When heated, calcium carbonate decomposes to yield calcium oxide and carbon dioxide gas via the reaction
How many grams of calcium carbonate are needed to produce 59.0L of carbon dioxide at STP?
1. Write the balanced equation.
2. Convert 59.0 L CO2 at STP to moles. moles = 59.0 L x (1 mole/22.4 L) = ??
3. Using the coefficients in the balanced equation, convert moles CO2 to moles CaCO3.
4. Convert moles CaCO3 to grams.
grams = moles x molar mass.