Homework Help: Math cont.

Posted by Jordan on Friday, October 16, 2009 at 12:47pm.

The neighborhood skateboard club is starting a fundraiser in order to buy more skateboards. They have decided to sell logo mugs. The Mugs on Mugs Company offers to supply mugs to the club for $3.75 each plus a $55 process and handling fee. The Punny-Cups Company offers to supply mugs to the club for $5.05 each plus a $10 process and handling fee. How many mugs would they have to buy to make the cost the same from both companies? Round your answer up to the nearest one mug. Define two variables, write a system of equations, and solve the system by graphing on your own paper to find the number of mugs. Include the intersection point in your explanation.
mugs on mugs cost=3.75n+55 Punny-cups cost=5.05n+10 3.75(35)+55= 186.25-- 187. 5.05(35)+10= 186.75-- 187. intersection point= (34.04, 182.65)

mugs on mugs cost=3.75n+55
Punny-cups cost=5.05n+10

3.75(35)+55= 186.25-- 187.
5.05(35)+10= 186.75-- 187.

intersection point= (34.04, 182.65)

Heres my question:
Under what circumstances should the club choose the Mugs on Mugs Company? Under what circumstances should the club choose the Punny-Cups Company? Assume that the companies produce mugs of equal size and quality.

Math cont. - MathMate, Friday, October 16, 2009 at 1:07pm
Check the cost from each company for 20 mugs. Do the same for 60 mugs.
If you have to pay for the mugs, what would you do in each of the cases?

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