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March 30, 2015

March 30, 2015

Posted by **Salman** on Friday, October 16, 2009 at 7:25am.

- Math -
**Reiny**, Friday, October 16, 2009 at 8:06amDid you make a diagram?

Let the time passed since noon be t hours

so the distance covered by ship B since then is 22t, and the distance covered by A since noon is 16t

Let the distance between the ships be D

I see a right-angled triangle where

D^2 = (16t+30)^2 + (22t)^2

2D(dD/dt) = 2(16t+30)(16) + 2(22t)(22)

dD/dt = (740t+480)/D

at 7:00 pm, t = 7 and

D^2 = 43880

D = √43880 = 209.476

and

dD/dt = (740(7)+480)/√43880 = 27.02 knots

check my arithmetic, I tend to make errors so early in the morning before my third cup of coffee.

- Math -
**Salman**, Friday, October 16, 2009 at 8:19amThe answer is correct. Thank u for ur help.

- Math -
**Lena**, Monday, March 21, 2011 at 7:20pmThank you very much for your help. everything makes sense and I got 100% on my answer.

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