posted by Chan on .
The coefficient of static friction between the m = 3.20 kg crate and the 35.0° incline of the figure below is 0.340. What minimum force must be applied to the crate perpendicular to the incline to prevent the crate from sliding down the incline?
I assume a crate is on an incline.
In this case, fricion + force applied has to be greater than the component of weight down the plane.
weight down plane: mgSinTheta
force+friction=weight down plane
solve for force.