Posted by **help please:)** on Thursday, October 15, 2009 at 11:44pm.

Yesterday Lucy walked 2 hours and jogged 1/2 hour and covered 6.25 miles. Today she walked for 3 hours and jogged for 1 hour and covered 10.25 miles. Assuming a constant walking rate and a constant jogging rate, how fast did she walk and how fast did she jog? Define two variables, write a system of equations, and solve to find the walking rate and the jogging rate. Justify your answer by showing how you solved the problem.

w- walking j- jogging

2w + .5j= 6.25 --> 3(2w+.5j)= 3(6.25)

3w + 1j= 10.25 --> -2(3w+1j)= -2(10.25

6w + 1.5j= 18.75

-6w - 2j= -20.50

-----------------

-.5j=-1.75

j=.3

2w + .5(.3)= 6.25

2w + 15= 6.25

2w= 6.10 w= 3.05

check:

2(3.05) + .5(.3)= 6.25 (correct)

3(3.05) + 1(.3)= 9.45(wrong!!) it should be 10.25.

Where am i going wrong?

## Answer this Question

## Related Questions

- 11th grade - Yesterday Lucy walked 2 hours and 1/2 jogged hour and covered 6.25 ...
- algebra...redo. - Yesterday Lucy walked 2 hours and jogged 1/2 hour and covered ...
- algebra - Yesterday Lucy walked 2 hours and jogged 1/2 hour and covered 6.25 ...
- algebra - Jean jogged for 2 miles and then walked for 3 miles. Took her 1 1/3 ...
- math - Tom and kate live 15 miles apart they decide to jog to meet eachother ...
- math - Two friends worked out on treadmills at the gym. •Alden walked 2 miles in...
- VNS,Math - A man walked into the road at 4 miles per hour and returned over the ...
- math - The equation d =70t represents the distance in miles covered after ...
- algebra - write a linear equation to model the situation. you have walked 4 ...
- Math HELP! - Find the unit rate. Rounf to the nearest tenth, if necassary. 344 ...

More Related Questions