Textrodotoxin is a toxic chemical found in fugu pufferish, a popular but rare delicacy in Japan. The compound has a LD50 (the amount of substance that is lethal to 50% of a population of iron (iii) hydroxide. Textrodotoxin is 41.38% carbon by mass, 13.16% nitrogen by mass, and 5.37% hydrogen by mass, with the remaining amount consisting of oxygen.

You didn't finish the question. I assume you want to know the empirical formula.

Take a 100 g sample,
That will give you
41.38 g carbon.
13.16 g nitrogen.
5.37 g hydrogen.
100-sum of above = g oxygen.

Convert each of the grams to moles, then find the ratio of them in small whole numbers. (Divide the smallest number by itself to make it 1.00, then divide all of the others by the same small number.) Round to whole numbers (but don't found anything between xx.25 and xx.75). I think you will come out with xx.67. The way to get rid of that is to multiply all of the numbers by 3 and you should get very close to whole numbers for all of them. This gives the reported empirical formula for the compound.

Thanks! That helps me a lot to answer the remaining parts of the question.

To calculate the molar mass of tetrodotoxin, we need to determine the number of moles of each element present in the compound.

1. Start by assuming we have 100g of tetrodotoxin. This means that 41.38g is carbon, 13.16g is nitrogen, and 5.37g is hydrogen.

2. Convert the mass of each element to moles. To do this, divide each mass by the molar mass of the respective element.
- The molar mass of carbon (C) is 12.01 g/mol, so the number of moles of carbon is 41.38g / 12.01 g/mol = 3.447 mol.
- The molar mass of nitrogen (N) is 14.01 g/mol, so the number of moles of nitrogen is 13.16g / 14.01 g/mol = 0.938 mol.
- The molar mass of hydrogen (H) is 1.01 g/mol, so the number of moles of hydrogen is 5.37g / 1.01 g/mol = 5.317 mol.

3. Subtract the total number of moles of carbon, nitrogen, and hydrogen from 100g, since the remaining mass is oxygen.
- The mass of oxygen is 100g - (41.38g + 13.16g + 5.37g) = 40.09g.

4. Convert the mass of oxygen to moles by dividing by the molar mass of oxygen. The molar mass of oxygen (O) is 16.00 g/mol, so the number of moles of oxygen is 40.09g / 16.00 g/mol = 2.51 mol.

5. Now, we can calculate the molar mass of tetrodotoxin by adding up the molar masses of carbon, nitrogen, hydrogen, and oxygen.
- The molar mass of tetrodotoxin = (3.447 mol C * 12.01 g/mol) + (0.938 mol N * 14.01 g/mol) + (5.317 mol H * 1.01 g/mol) + (2.51 mol O * 16.00 g/mol) = 162.19 g/mol.

Therefore, the molar mass of tetrodotoxin is 162.19 g/mol.