a photograph measures 9 in by 12 in. earl put it in a frame that addded 2in to everyside. find the ouside perimeter and total of the photograph and frame.

I will be happy to check your work.

would i add all the numbers toegther ?

You need to tell us what the formula for a perimeter is before you can solve this problem.

After you post that information, we'll try to help you.

would the formula be p for piermeter adding the numbers?

You're getting there.

What numbers do you add to find the perimeter?

would i add 9 +12?

That's partly right.

Study this web site to learn what a perimeter is.

http://www.mathopenref.com/rectangleperimeter.html

would i add 9+9+12+12?

Yay! You've got it!!!!

The perimeter of the photo is:

(2 * 9) + (2 * 12 = 18 + 24
18 + 24 = 42 inches
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Now add 2 inches to each side.

4 + 9 = 13
4 + 12 = 16

(2 * 13) + (2 * 16) = 26 + 32
26 + 32 = 58 inches for the perimeter of the frame

To find the outside perimeter of the photograph and frame, we need to add the dimensions of the photograph and the dimensions added by the frame.

The photograph measures 9 inches by 12 inches.

The frame adds 2 inches to every side. So, the dimensions of the photograph and frame will be:

Length: 9 inches + 2 inches (added on each side) + 2 inches (added on each side) = 9 + 2 + 2 = 13 inches

Width: 12 inches + 2 inches (added on each side) + 2 inches (added on each side) = 12 + 2 + 2 = 16 inches

To find the outside perimeter, we can use the formula:

Perimeter = 2 * (Length + Width)

Substituting the values:

Perimeter = 2 * (13 inches + 16 inches) = 2 * (29 inches) = 58 inches

Therefore, the outside perimeter of the photograph and frame is 58 inches.

To find the total area of the photograph and frame, we can simply multiply the length and width:

Area = Length * Width

Substituting the values:

Area = 13 inches * 16 inches = 208 square inches

Therefore, the total area of the photograph and frame is 208 square inches.