Two identical ballons are filled, one w/ argon the other w/ oxygen gas at the same temp. If the oxygen ballon leaks at the rate of 64 mL per hour, how many hours will it take the argon ballon to lose 195mL of argon gas?
so far this what i have now i am stuck
Its 64/r2 = sqrt(39.95/32)=57.28
So argon leaks at the rate of 57.3 mL/hr.
and 195 mL x (1 hr/57.3 mL) = ?? hours.?
Check my thinking.