Wednesday
July 23, 2014

Homework Help: Physics

Posted by Ian on Thursday, October 15, 2009 at 8:10pm.

Question:
Two masses 2.2 Kg and 3.2 Kg connected by a rope over a massless and frictionless pulley hang at 1.8 m above the ground on either side of the pulley. The pulley is 4.8 m above the ground. What is the maximum height that the 2.2 Kg weight will rise to after the system is released.


Work so far:
A= ((m2-m1)/(m2+m1))* 9.8 = 1.81 m/sec^2

So in one second the 3.2 Kg weight is going to fall to the ground and via the rope pull the 2.2 Kg weight up to 3.6 m but it will have an initial acceleration of -1.81 m/sec and so will travel higher than 3.6 m(1.8m + 1.8m).

Gravity is pulling down on 2.2 Kg weight at 9.8 m/sec^2.

How do I know how to find the height the 2.2 Kg weight rises to given its initial acceleration of -1.81 m/sec^2.

The answer is 3.94 m

Thank you - I hope the problem description is clear.

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