Posted by Anonymous on Thursday, October 15, 2009 at 7:12pm.
a jet fighter plane is launched from a catapult on an aircraft carrier. it reaches a speed of 42 m/s at the end of the catapult in 2 sec. if the acceleration is constant, what is the length of the catapult?

physics  bobpursley, Thursday, October 15, 2009 at 7:24pm
vf^2=2*acceleration*distance
solve for acceleration 
physics  andrusia, Monday, September 27, 2010 at 10:28pm
Use the formula V=change in distance/chance in time
Equation looks like this:
42m/s= x/2
solve for x