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11th grade

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Yesterday Lucy walked 2 hours and 1/2 jogged hour and covered 6.25 miles. Today she walked for 3 hours and jogged for 1 hour and covered 10.25 miles. Assuming a constant walking rate and a constant jogging rate, how fast did she walk and how fast did she jog? Define two variables, write a system of equations, and solve to find the walking rate and the jogging rate. Justify your answer by showing how you solved the problem.


w- walking j- jogging
2w + .5j= 6.25 --> 3(2w+.5j)= 3(6.25)
3w + 1j= 10.25 --> -2(3w+1j)= -2(10.25

6w + 1.5j= 18.75
-6w - 2j= -20.50
-----------------
-.5j=-1.75
j=.3


2w + .5(.3)= 6.25
2w + 15= 6.25
2w= 6.10 w= 3.05

check:
2(3.05) + .5(.3)= 6.25 (correct)
3(3.05) + 1(.3)= 9.45(wrong!!) it should be 10.25.

  • 11th grade - ,

    since when is 1.75/5 = .3?

  • 11th grade - ,

    -.5/1.75= -.2857...or .3

  • 11th grade - ,

    Lord, Jordan.
    you have a*x=b
    then x= b/a NOT a/b

  • 11th grade - ,

    I get 1.75/.5=3.5
    check that.

  • 11th grade - ,

    wow haha im lost...
    6w + 1.5j= 18.75
    -6w - 2j= -20.50
    -----------------
    -.5j=-1.75
    j=.3

    ? why would i multiply?

  • 11th grade - ,

    Jordan, this is pretty basic.

    .5 j= 1.75
    divide both sides by .5
    j= 1.75/.5

  • 11th grade - ,

    But, if i did get 3.5 that would mess up getting 6.25 or 10.25.

    2(3.05) + .5(.3)= 6.25--correct.
    3(3.05) + 1(.3)= 9.45... this is the one where i went wrong. i went wrong.

  • 11th grade - ,

    You have a lot of problems. YOu solved j as 3.5 so now solve for w, you first answer is WRONG.

    2w + .5(3.5)= 6.25 solve for w.

  • 11th grade - ,

    Jordan, if you are in ALG II, I recommend a tutor before you get lost.

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