Homework Help: algebra...redo.

Posted by jordan on Thursday, October 15, 2009 at 1:18pm.

Yesterday Lucy walked 2 hours and jogged 1/2 hour and covered 6.25 miles. Today she walked for 3 hours and jogged for 1 hour and covered 10.25 miles. Assuming a constant walking rate and a constant jogging rate, how fast did she walk and how fast did she jog? Define two variables, write a system of equations, and solve to find the walking rate and the jogging rate. Justify your answer by showing how you solved the problem.

w- walking j- jogging
2w + .5j= 6.25 --> 3(2w+.5j)= 3(6.25)
3w + 1j= 10.25 --> -2(3w+1j)= -2(10.25

6w + 1.5j= 18.75>> -.5j=-1.75
-6w - 2j= -20.50 >> j=.3

2w + .5(.3)= 6.25
2w + 15= 6.25
2w= 6.10 w= 3.05

check:
2(3.05) + .5(.3)= 6.25 (correct)
3(3.05) + 1(.3)= 9.45(wrong!!) it should be 10.25.

algebra...redo. - MathMate, Thursday, October 15, 2009 at 3:22pm
Up to this line, things are OK.
-6w - 2j= -20.50 >> j=.35
Could you continue and check?

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