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March 25, 2017

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A 1.50x10cube is going up a road inclined at 10degrees. If the coefficient of friction is 0.7. Determine the force that will move the car up the inclined with a constant speed.

Given:
m=1.50x10cube
angle=10degrees
coefficient=0.7

Required:
F=?

PLEASE HELP..

  • Physics - ,

    the component of weight down the hill is mg*SinTheta.
    The component of weight normal to the hill is mg*CosTheta
    Friction down the hill is mg*mu*CosTheta

    So the force down the hill is mg*mu*CosTheta+mgSinTheta
    That force must be overcome to move the car up the hill.

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