Posted by Sam on Wednesday, October 14, 2009 at 9:03pm.
Leg traction is applied to a patient's leg as shown in the figure below. If the physician has requested a 57 N force to be applied to the leg, and the angle is θ = 60o , what mass m must be used for the object hanging from the massless cable?
So < represents angle formed shown at 2 tetra split by horizontal.
- Physics - MathMate, Wednesday, October 14, 2009 at 9:46pm
I wish I could understand the figure, but as it is, it looks to me that all the weight added is supported by the ceiling.
- Physics - Gharib, Monday, October 25, 2010 at 2:50pm
You have to make two FBD; 1st for the force being applied to the leg, and 2nd for the mass hanging from cable.
Positive being up and right.
Y direction for FBD #2: T= mg Eq 1
x direction for FBD #1: -F+2Tcos(60)=0 Eq 2
From Eq 1, m=x/g
that's your answer.
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