Posted by **CM** on Wednesday, October 14, 2009 at 10:39am.

When asked about their driving, 56% of students say they are better than the average driver, 39% say they are an ave. driver and the rest say they are worse than ave. A pair of students are driving home together for break. What is the probability that at least one student said they were worse than average as a driver?

What I have so far is:

P(at least one student said they were worse ave. driver)

= 1 - P(no students saying they were worse than ave. driver)

= 1- (0.95????

I am confused here. Please help and show work so I can understand.

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