Posted by **CM** on Wednesday, October 14, 2009 at 10:39am.

When asked about their driving, 56% of students say they are better than the average driver, 39% say they are an ave. driver and the rest say they are worse than ave. A pair of students are driving home together for break. What is the probability that at least one student said they were worse than average as a driver?

What I have so far is:

P(at least one student said they were worse ave. driver)

= 1 - P(no students saying they were worse than ave. driver)

= 1- (0.95????

I am confused here. Please help and show work so I can understand.

## Answer This Question

## Related Questions

- English - My address is 34 Park Ave., New York ================== Is the ...
- calc check: average value - Find the average value of the function "f(x) = x^2 ...
- calc: avg value - Find the average value of the function "f(x) = x^2 sqrt(1+x^3...
- Japanese language help - I have marked my answer with a â˜…, if I am wrong could...
- English - 1. I don't know who to say. 2. I don't know who to say to. 3. I don't ...
- physics - A test car with a dummy driver of mass 60 kg was propelled towards a ...
- English - Okay got that one.. What about The cab driver was driving extremely ...
- Science - The rest stops the driver made are included in the calculations ...
- algebra inequalities - can you check these tell if the number after the: color ...
- Math - Let's say I work in a store and a costmer walks up to me and asks me how...

More Related Questions