Posted by Katie on Tuesday, October 13, 2009 at 9:47pm.
my first line after using the product rule would be
(2x-1)^4(-1)(4x+1)^-2(4) + (4x+1)^-1(5)(2x-1(^4(2)
= -4(2x-1)^5(4x+1)^-2 + 10(4x+1)^-1(2x-1)^4
= (2x-1)^4(4x+1)^-2[-4(2x-1) + 10(4x+1)]
= (2x-1)^4(4x+1)^-2(32x + 14)
= 2(2x-1)^4(4x+1)^-2(16x+7)
perhaps your teacher will not insist that you completely simplify it.
I expected my students to arrive at the above answer.
Related Questions
bryce - can someone help me write out these expressions? 4 more than p: product ...
Calculus - How do I use the chain rule to find the derivative of square root(1-x...
calculus help - Is there any good calculus websites out there that teach every ...
Pre-Calc - Could someone show me how to solve these two problems-I have 10 of ...
Calculus - Could someone please check my work on the following problems? I want ...
Math 157 - Can someone please help me. At a quality control checkpoint on a ...
Math - Can someone please help me. At a quality control checkpoint on a ...
Calculus - f(x)=5+(6/x)+(7/x^2), find f'(x). I haven't done fractions ...
Pre-Algebra ... again :-( - How do i go about finding the integers of a product ...
Calculus Derivative - I'm trying to calculate the derivative of this: P= mv...
For Further Reading
