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August 27, 2014

Homework Help: Chemistry

Posted by Anonymous on Tuesday, October 13, 2009 at 7:40pm.

If I have 0.17g of Mg and 0.10g of O, and I am asked to find the empirical formula for magnesium oxide, is the following the right way to go about it?

Convert g-> mol
0.17g=0.01mol Mg
0.10g=0.01mol O

Divide by smallest mole amt. (0.01mol)
0.01mol/0.01mol=1
0.01mol/0.01mol=1

Therefore,
1Mg1O
MgO is the empirical formula. Right?

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