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December 18, 2014

December 18, 2014

Posted by **Trevor** on Tuesday, October 13, 2009 at 7:28pm.

1. cos x/(1-sinx)= sec x + tan x

2. (tanx+1)^2=sec^2x + 2tan x

3. csc x = )cot x + tan x)/sec x

4. sin2x - cot x = -cotxcos2x

- Math - Trigonometry -
**Reiny**, Tuesday, October 13, 2009 at 8:04pmHint:

change all trig ratios to sines and cosines.

I will do one for you.

3. csc x = (cot x + tan x)/sec x

RS = (cosx/sinx + sinx/cosx)/(1/cosx)

= (cos^2 x + sin^2 x)/(sinxcosx) * cosx

= (1/(sinxcosx)(cosx)

= 1/sinx

= csc x

= LS

- Math - Trigonometry -
**Anonymous**, Wednesday, February 24, 2010 at 9:42pmI dont know

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