Posted by Anonymous on Tuesday, October 13, 2009 at 5:24pm.
no, you forgot about the inequality condition.
You must have had
(x-5)(x+2) ≤ 0
here is a neat way to finish it
draw a line and mark the "critical values" of -2 and +5
this splits the line into 3 segments
1. x < -2
2. x between -2 and 5
3. x > 5
pick any x you want in each of the segments to test . You don't actually have to find the value just the +/- situation
1. let x = -10 , so (-)(-) > 0 , NO
2. let x = 0 , so (-)(+) < 0 YEs
3. let x = 10, then (+)(+) > 0, NO
so every value of x between -2 and 5 inclusive will work..
-2 ≤ x ≤ 5 , x any real number
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