Posted by **DJ** on Tuesday, October 13, 2009 at 5:07pm.

A box is given a push so that it slides across the floor. How far will it go, given that the coefficient of kinetic friction is 0.15 and the push imparts an initial speed of 3.9 m/s?

- physics -
**MathMate**, Tuesday, October 13, 2009 at 7:04pm
Acceleration, a = -μg

initial velocity, v0 = 3.9 m/s

final velocity, v = 0 m/s

Using

2aS=v²-v0², where

Distance to stop, S = (v²-v0²)/(2a)

- physics -
**Anonymous**, Thursday, November 12, 2015 at 11:43am
300

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