Posted by thomas on Tuesday, October 13, 2009 at 5:06pm.
just wondering if someoen could help me with this limit..:
lim arctan[(x^2  4)/(3x^26x)]
x>2

calculus  Reiny, Tuesday, October 13, 2009 at 5:26pm
My first step in doing limits is to sub in the approach value, this will give me Lim arctan (0/0)
This just about guarantees that the algebraic expression will factor and the offending factor will cancel.
Sure enough
lim arctan[(x^2  4)/(3x^26x)] x>2
= lim arctan[(x+2)(x2)]/[3x(x2)]
=lim arctan[(x+2)]/[3x]
= lim arctan(2/3)
now use your calculator, set to radian mode, to find
lim arctan[(x^2  4)/(3x^26x)] x>2
= .588

calculus  thomas, Tuesday, October 13, 2009 at 5:30pm
thanks for the reply... the question asks me to evaluate the limit using continuity, how do i justify my answer with continuity?
Answer This Question
Related Questions
 Calculus  Note that pi lim arctan(x ) =  x > +oo 2 Now evaluate / pi \ ...
 Calculus  I am maybe overthinking this, but what is the lim as n> infinity ...
 limiting position of the particle  A particle moves along the x axis so that ...
 Calculus  Find the limit. lim 5x/(x^225) x>5 Here is the work I have so ...
 Calculus. Limits. Check my answers, please! :)  4. lim (tanx)= x>pi/3 (...
 calculus again  Suppose lim x>0 {g(x)g(0)} / x = 1. It follows necesarily ...
 Calculus  Show that limit as n approaches infinity of (1+x/n)^n=e^x for any x&...
 Calculus (lim)  consider the statement lim x³6x²+11x6 / x1 = 2 x>1 Using...
 Calculus  Show that limit as n approaches infinity of (1+x/n)^n=e^x for any x&...
 calculus  lim (x^31)/(x^3+2x^2y+xy^2x^22xyy^2) (x,y)>(1,0) my question ...
More Related Questions