Posted by ellen on Tuesday, October 13, 2009 at 3:59am.
when y=sinx and y=sin2x  sinx are added together and graphed, why do the maximum values of two sin functions occur where they do?

math  Reiny, Tuesday, October 13, 2009 at 8:36am
your new function is
y = (sin 2x  sinx) + sinx
= sin2x
notice your amplitude has not changed, so the maximum value is still 1.
your period is now 2pi/2 or 360º/2
= pi radians or 180º
If you look at the first complete graph, doesn't it reach its maximum at the end of the first quarter of its period?
And that would be pi/4 or 45º
check: what is sin (2*45º) ?
Answer This Question
Related Questions
 Trig Help  Prove the following: [1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx...
 Math (trigonometric identities)  I was given 21 questions for homework and I ...
 Math Help  Hello! Can someone please check and see if I did this right? Thanks...
 math  y= 2sin^2 x y=1 sinx find values of x inthe interval 0<x<360 if ...
 Trig........  I need to prove that the following is true. Thanks (cosx / 1sinx...
 Trigonometry.  ( tanx/1cotx )+ (cotx/1tanx)= (1+secxcscx) Good one! Generally...
 calculus  Could someone check my reasoning? thanx Find the derivative of the ...
 Trig  Simplify sin x cos^2xsinx Here's my book's explanation which I don't ...
 Math  1) evaluate without a calculator: a)sin(3.14/4) b) cos(3(3.14)/4) c) tan...
 Mathematics  Trigonometric Identities  Prove: (tanx)(sinx) / (tanx) + (sinx...
More Related Questions