Posted by **ellen** on Tuesday, October 13, 2009 at 3:59am.

when y=-sinx and y=sin2x - sinx are added together and graphed, why do the maximum values of two sin functions occur where they do?

- math -
**Reiny**, Tuesday, October 13, 2009 at 8:36am
your new function is

y = (sin 2x - sinx) + sinx

= sin2x

notice your amplitude has not changed, so the maximum value is still 1.

your period is now 2pi/2 or 360º/2

= pi radians or 180º

If you look at the first complete graph, doesn't it reach its maximum at the end of the first quarter of its period?

And that would be pi/4 or 45º

check: what is sin (2*45º) ?

## Answer This Question

## Related Questions

- Trig Help - Prove the following: [1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx...
- Math (trigonometric identities) - I was given 21 questions for homework and I ...
- Math Help - Hello! Can someone please check and see if I did this right? Thanks...
- math - y= 2sin^2 x y=1- sinx find values of x inthe interval 0<x<360 if ...
- Trig........ - I need to prove that the following is true. Thanks (cosx / 1-sinx...
- Trigonometry. - ( tanx/1-cotx )+ (cotx/1-tanx)= (1+secxcscx) Good one! ...
- calculus - Could someone check my reasoning? thanx Find the derivative of the ...
- Trig - Simplify sin x cos^2x-sinx Here's my book's explanation which I don't ...
- Math - 1) evaluate without a calculator: a)sin(3.14/4) b) cos(-3(3.14)/4) c) ...
- Mathematics - Trigonometric Identities - Prove: (tanx)(sinx) / (tanx) + (sinx...

More Related Questions