A 18000kg airplane lands with a speed of 77 m/s on a stationary aircraft carrier deck that is 115 m long.
Find the work done by nonconservative forces in stopping the plane.
I have an exam on this tomorrow and I am confused any help would be appreciated.
To find the work done by nonconservative forces in stopping the plane, we need to calculate the initial kinetic energy and the final kinetic energy of the airplane.
The initial kinetic energy of the airplane can be calculated using the formula:
Kinetic energy = 0.5 * mass * velocity^2
= 0.5 * 18000 kg * (77 m/s)^2
= 0.5 * 18000 kg * 5929 m^2/s^2
= 53,205,000 J (rounded to the nearest whole number)
Next, we need to find the final kinetic energy of the airplane. Since the plane is brought to a stop, the final velocity is 0 m/s.
Final kinetic energy = 0.5 * mass * final velocity^2
= 0.5 * 18000 kg * (0 m/s)^2
= 0 J (the final kinetic energy is zero since the plane is at rest)
The work done by nonconservative forces can be calculated using the formula:
Work done = Initial kinetic energy - Final kinetic energy
= 53,205,000 J - 0 J
= 53,205,000 J
Therefore, the work done by nonconservative forces in stopping the plane is 53,205,000 Joules.