Post a New Question

algebra

posted by .

(3x squared-10x)divided by(x-6)=3x+8+48/x-6. but i have no idea how thaproblem was done. pls show me the steps

  • algebra - ,

    I assume that you mean:

    (3x^2 - 10x)/(x-6) = (3x + 8 + 48)/(x-6)

    If so, multiply both sides by x - 6.

    3x^2 - 10x = 3x + 56

    Subtract 3x from both sides.

    3x^2 - 13x = 56

    Factor out x to give you:

    x(3x -13) = 56

    x = 56 or

    3x - 13 = 56
    3x = 69
    x = 23

    I hope this helps. Thanks for asking.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question