Posted by kt on Monday, October 12, 2009 at 7:40pm.
Assuming you are using angle rotation convention, that would put point P into the 4th quadrant.
After drawing the triangle with hypotenuse of 7 and angle of 60º, we can see that
sin -60 = y/7 ----> y = 7(sin -60º) = -6.06
cos -60º = x/7 = 7cos -60º = 3.5
so P is (3.5,-6.06)
or
we could have used the ratios of sides of the 30-60-90 triangle which are 1:√3:2
then x:y:7 = 1:√3:2
x/1 = 7/2 ---> x = 3.5
y/√3 = 7/2 ---> y = 7√3/2 = 6.06
Realizing where P is located,
P is (3.5,-6.06)
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