Posted by Anonymous on Monday, October 12, 2009 at 7:07pm.
Which of these rational functions has a ) horizontal asymptote? a slant asymptote? no vertical asymptote?
r(x)= 2x1/ x^2x2 = 2x1/ (x2)(x+1)
s(x)= x^3+27/x^2+4 = (x+3)(x^23x+9)/(x2)(x+2)
t(x)=x^39x= x(x3)(x+3)/x+2
u(x)=x^2+x6/x^225= (x+3)(x2)/(x+5)(x5)
I do not know how to determine the asymptotes. Please help me. I would sincerely appreciate it. Thanks!

Calculus  MathMate, Monday, October 12, 2009 at 8:28pm
Vertical asymptotes are typically present in functions with a polynomial denominator. The vertical asymptote is located where the value of x is such that the denominator is zero. If the denominator is not a polynomial, the same applies whenever the denominator becomes zero.
To find horizontal asymptotes, you would divide the polynomials by long division.
If the result is of the form p+q/P(x), where p and q are integers and P(x) is a polynomial, the horizontal asymptote is y=p, since the second term vanishes when P(x) becomes infinity.
If the result of the long division is px+q+r/P(x), then the line y=px+q is the oblique asymptote, again, the last term vanishes as x becomes infinity.
You can conclude that the function has no vertical asymptote when the denominator does not vanish for all real values of x.
If you need a check on the answers, feel free to post.
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