If 150.0 Ml of HCL solution are required to react completely with .35 moles of solid NaOH whats the molarity of the solution?
Moles HCl=molesNaOH
.150*M=.35
solve for M.
To find the molarity of the HCl solution, we need to use the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
Given:
- Moles of NaOH (solute) = 0.35 moles
- Volume of HCl solution = 150.0 mL
Before we proceed, we need to convert the volume from milliliters (mL) to liters (L) since the molarity should have a unit of moles per liter.
1 mL = 0.001 L
So, 150.0 mL = 0.150 L
Now, we can calculate the molarity by dividing the moles of solute by the volume of the solution:
Molarity (M) = 0.35 moles / 0.150 L
By performing this calculation, we find that the molarity of the HCl solution is approximately 2.33 M.