Posted by **Bill** on Monday, October 12, 2009 at 2:36am.

A stone, initially at rest, is dropped from the top of a building. On its way down, it passes a window that is 2.52m tall. It takes 0.134 seconds to pass the window. From how far above the top of the window was the stone dropped?

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**drwls**, Monday, October 12, 2009 at 6:41am
Let H be the distance from the top of the building to the top of the window.

Let T be the time for the stone to reach that point. g = 9.91 m/s^2

Here is what you knmow:

H = (1/2) g T^2

H + 2.25 = (1/2) g (T + 0.134)^2

Combining the two equations, you can eliminate H

2.25 = (1/2) g [0.268 T + 0.018]

Solve that for T; then compute H with one of the original equations.

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