Posted by Andy on Sunday, October 11, 2009 at 11:59pm.
g of a spherical body is proportional to M/R^2.
Therefore, g on the surface of Pluto will be lower than that of Earth, by a factor
2.5*10^-3*/0.18^2 = 0.077
That means the value of g for Pluto (which I will call g') is 0.75 m/s^2
Use the standard formula for the distance fallen:
X = (1/2)g' t^2, where t = 1.1 s.
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