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March 1, 2015

March 1, 2015

Posted by **Becky** on Sunday, October 11, 2009 at 11:37pm.

(a) How long is the rocket in motion above the ground?

(b) What is its maximum altitude?

(c) What is its velocity just before it collides with the Earth?

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For A, I solved it such that it was the sqrt of the initial velocity squarted + 2(acceleration times final height of rocket) = 43.8 S, but that was incorrect. For B and C, I'm a bit lost as to what to do.

- Physics -
**MathMate**, Monday, October 12, 2009 at 10:49amIf you use

S=v0*t + (1/2)at²

you have

S=960m

v0=80.2 m/s

a=4.2 m/s²

Solve for t.

I get 9.6 sec. for going up, and 14 sec. for coming down (v0=0,a=-g,S=-960).

Check my work and post if you would like to check answers.

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