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March 28, 2017

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A ball, dropped from rest, cover 2/7 of the distant to the ground in the last 2 seconds of its fall. From what height was the ball dropped? What was the total time of the fall?

  • Physics - ,

    Let T be the total time to hit the ground.
    Let H be the height it is dropped from.

    H = (g/2) T^2
    (5/7) H = (g/2)(T-2)^2

    Two equations, two unknowns. H can be eliminated easily.

    (5/7)H = (5/14) g T^2
    (5/7)H = (g/2)(T-2)^2

    Solve for T first, then solve for H

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