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September 2, 2014

September 2, 2014

Posted by **Anonymous** on Sunday, October 11, 2009 at 12:06am.

- physics -
**MathMate**, Sunday, October 11, 2009 at 12:27amCliff Height, H = -42.9 m

Time to drop down cliff, t

H=0*t + (1/2)*(-g)t²

t=√(2*H/(-g))

Time for sound to travel, ts

= 3.16-t

Oblique distance,D = ts s. * 343 m/s

Horizontal distance h= √(H²+D²)

initial horizontal velocity, u

= horizontal distance / time to reach bottom

= h/t

Please check my thinking.

- physics -
**Anonymous**, Sunday, October 11, 2009 at 1:22amI got the right answer.

However, the equation to find the horizontal distance would be:

h = square root of (D^2 - H^2)

- physics -
**MathMate**, Sunday, October 11, 2009 at 7:52amYes, you are correct, since the oblique distance is the hypotenuse.

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