Posted by Anonymous on Sunday, October 11, 2009 at 12:06am.
A soccer player kicks a rock horizontally off a cliff 42.9 m high into a pool of water. If the player hears the sound of the splash 3.16 s later, what was the initial speed given to the rock? Assume the speed of sound in air to be 343 m/s.

physics  MathMate, Sunday, October 11, 2009 at 12:27am
Cliff Height, H = 42.9 m
Time to drop down cliff, t
H=0*t + (1/2)*(g)t²
t=√(2*H/(g))
Time for sound to travel, ts
= 3.16t
Oblique distance,D = ts s. * 343 m/s
Horizontal distance h= √(H²+D²)
initial horizontal velocity, u
= horizontal distance / time to reach bottom
= h/t
Please check my thinking. 
physics  Anonymous, Sunday, October 11, 2009 at 1:22am
I got the right answer.
However, the equation to find the horizontal distance would be:
h = square root of (D^2  H^2) 
physics  MathMate, Sunday, October 11, 2009 at 7:52am
Yes, you are correct, since the oblique distance is the hypotenuse.