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November 29, 2015
Posted by **Suchi** on Friday, October 9, 2009 at 8:58pm.

- Alg 2 hon -
**Suchi**, Friday, October 9, 2009 at 9:14pmPlease show work...

- Alg 2 hon -
**MathMate**, Friday, October 9, 2009 at 9:18pmPlease show us your thinking and problems if you have any.

- Alg 2 hon -
**Suchi**, Friday, October 9, 2009 at 9:24pmwell i got this so far:

total d = 1500 km

total time to get to destination = t(subscript)1 which is also equal to time taken to travel 1200 km back home.

Then I used d=rt formula,

I tried 1500 = 600 (t(subscript)1)

t(subscript)1=2.5hrs

2.5hrs =1200 km on return flight

1200r (2.5)

r = 480km/h

1500 = 480 t(subscript)2.

that meant 600 - 480 would be 120 km/h but when i checked my answer, it said that the answer is 66 2/3 km/h... i am confused... PLZ HELP!!!

- Alg 2 hon -
**MathMate**, Friday, October 9, 2009 at 9:38pm66 2/3 is correct.

You would want to denote the unknown by a variable name, say v for velocity of wind.

The question stated that the time to travel 1500 km (with the wind) is the same as that required to travel 1200 km back (against the wind).

Can you express the previous paragraph in terms of the wind velocity, v, the air speed of 600 km/h and the distances 1500 and 1200?

If you can, solve it and you should get your required answer of 66 2/3. If not, post again.

- Alg 2 hon -
**Suchi**, Friday, October 9, 2009 at 9:42pmsry, I don't understand :[...

- Alg 2 hon -
**MathMate**, Friday, October 9, 2009 at 9:46pm"The question stated that the time to travel 1500 km (with the wind) is the same as that required to travel 1200 km back (against the wind). "

Time to traval to destination

= Distance / velocity

= 1500 / (600 + v)

Time to return (part of the way)

= Dostance / velocity

= ...

Equate the two, since they are equal and solve for v.

Can you take it from here?

- Alg 2 hon -
**Suchi**, Friday, October 9, 2009 at 9:47pmOh... hold opn, let me try it!!! if I dont get it, I'll try to post what I did! if i do, then thanx!!

- Alg 2 hon -
**Suchi**, Friday, October 9, 2009 at 9:50pmTHANK YOU SO MUCH!!!!

- Alg 2 hon -
**MathMate**, Friday, October 9, 2009 at 9:53pmI am sure you can. If not, post anyway. If I don't reply tonight, it will be tomorrow.