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When 1 mol of a gas burns at constant pressure, it produces 2424 J of heat and does 6 kJ of work.

How do i calculate delta E for this problem? I tried q+w but that didn't work for me. I got the answer wrong.

  • Chemistry -

    ΔE = q - w
    ΔE is the change in internal energy of a system
    q is the heat flowing into the system
    w is the work being done by the system
    The 2424 J is released to the surroundings. It should be assigned a negative sign. The 6 KJ is work done against the surroundings. That is energy released, too. Assign algebraic signs carefully and see what value for delta E you get.

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