posted by keisha on .
A force of 70.0 N is exerted at an angle of 30.0° below the horizontal on a block of mass 8.00 kg that is resting on a table. What is the magnitude of the normal force acting on the block?
The upward component of the 70N force is
70.0N*sinTheta. Add that to the downward component, 8g, and you have the net force downward.