Hi!Question:Two packing crates of masses m1 = 10.0 kg and m2 = 6.50 kg are connected by a light string that passes over a frictionless pulley as in the figure below. The 6.50 kg crate lies on a smooth incline of angle 45.0°. Find the acceleration of the 6.50 kg crate.

_________m/s2 (up the incline)
Find the tension in the string.
_________ N
Thank you so much

I assume the m1 is hanging vertically. This is called an Atwood machine

the force of gravity acts on both, on m1,it is vertical, m1*g
On m2, it is downward,of course, but the component down the plane is m2*g*sinTheta

Net force=totalmass*acceleration
m1*g-m2*gsinTheta=(m1+m2)*a
solve for a.
The tension? at M1,
tension=m1*(g-a)

To find the acceleration of the 6.50 kg crate, we can use Newton's second law of motion: F = m * a, where F is the net force acting on the object, m is the mass of the object, and a is the acceleration.

In this problem, we have two masses connected by a light string. The 6.50 kg crate is on an incline, and the 10.0 kg crate is hanging vertically. The force causing the acceleration is the difference in the weights of the two crates.

First, let's find the weight of each crate. The weight of an object is given by the formula W = m * g, where W is the weight, m is the mass, and g is the acceleration due to gravity (approximately 9.8 m/s^2).

For the 10.0 kg crate:
Weight1 = m1 * g = 10.0 kg * 9.8 m/s^2

For the 6.50 kg crate on an incline, we need to consider the component of weight acting parallel to the incline. This component is given by W2_parallel = m2 * g * sinθ, where θ is the angle of the incline (45.0° in this case).

Weight2_parallel = m2 * g * sinθ = 6.50 kg * 9.8 m/s^2 * sin(45.0°)

Now, we can find the net force, F_net, acting on the 6.50 kg crate. F_net is equal to the difference between the weights of the two crates:

F_net = Weight1 - Weight2_parallel

Next, we need to determine the acceleration of the system. Since the two crates are connected by a light string, they will have the same acceleration (a). Thus, we can write:

F_net = (m1 + m2) * a

Now, we have two equations:

F_net = Weight1 - Weight2_parallel
F_net = (m1 + m2) * a

We can solve these equations simultaneously to find the acceleration, a.

To find the tension in the string, we can use the equation F_net = T, where T is the tension in the string.

Let's first find the acceleration.

ur dumb

AS_HOLES

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