Posted by Chloe on Friday, October 9, 2009 at 1:32am.
Let X be the distance before the finish line that the tortoise can get before the hare resumes running. The hare has 400 m to go, and will require 400/9 = 44.4 s to finish. The tortoise requires
X/0.54 seconds to finish.
For a close "photo finish",
44.4 s = X/0.54 m/s
X = 24 m
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